This question was previously asked in

UPRVUNL AE EC 2016 Official Paper

- \( Y(z)=\frac{16z^3}{{(z+0.5)}^2} \)
- \( Y(z)=\frac{4z^2}{{(z+0.5)}^2} \)
- \( Y(z)=\frac{4z^3}{{(z+0.5)}^4} \)
- \( Y(z)=\frac{16z^2}{{(z+0.5)}^4} \)

Option 4 : \( Y(z)=\frac{16z^2}{{(z+0.5)}^4} \)

Free

Hindi Subject Test 1

4248

10 Questions
10 Marks
10 Mins

__Concept:__

y(n) = x(n) * h(n)

Y(z) = X(z) H(z) ---(1)

__Calculation:__

Given:

\(X(z)=\frac{4z}{{(z+0.5)}^2} ;|z|>0.5\)

h(n) = x(n)

H(z) = X(z) ---(2)

From equation (1) and (2)

Y(z) = X(z) X(z) = [X (z)]^{2}

^{\( Y(z)=\frac{16z^2}{{(z+0.5)}^4} \)}

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